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Fuzz programs: print an error if loading the reproducer fails

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The fuzz programs were returning a nonzero status if they failed to load the
reproducer, but that's discreet and not informative. Make them also print an
error message.

Signed-off-by: Gilles Peskine <Gilles.Peskine@arm.com>
This commit is contained in:
Gilles Peskine 2023-05-12 13:18:08 +02:00
parent 501fb3abf3
commit 1f9d8a43c2
1 changed files with 14 additions and 0 deletions
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14
programs/fuzz/onefile.c
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@ -14,34 +14,48 @@ int main(int argc, char **argv)
FILE *fp;
uint8_t *Data;
size_t Size;
const char *argv0 = argv[0] == NULL ? "PROGRAM_NAME" : argv[0];
if (argc != 2) {
fprintf(stderr, "Usage: %s REPRODUCER_FILE\n", argv0);
return 1;
}
//opens the file, get its size, and reads it into a buffer
fp = fopen(argv[1], "rb");
if (fp == NULL) {
fprintf(stderr, "%s: Error in fopen\n", argv0);
perror(argv[1]);
return 2;
}
if (fseek(fp, 0L, SEEK_END) != 0) {
fprintf(stderr, "%s: Error in fseek(SEEK_END)\n", argv0);
perror(argv[1]);
fclose(fp);
return 2;
}
Size = ftell(fp);
if (Size == (size_t) -1) {
fprintf(stderr, "%s: Error in ftell\n", argv0);
perror(argv[1]);
fclose(fp);
return 2;
}
if (fseek(fp, 0L, SEEK_SET) != 0) {
fprintf(stderr, "%s: Error in fseek(0)\n", argv0);
perror(argv[1]);
fclose(fp);
return 2;
}
Data = malloc(Size);
if (Data == NULL) {
fprintf(stderr, "%s: Could not allocate memory\n", argv0);
perror(argv[1]);
fclose(fp);
return 2;
}
if (fread(Data, Size, 1, fp) != 1) {
fprintf(stderr, "%s: Error in fread\n", argv0);
perror(argv[1]);
free(Data);
fclose(fp);
return 2;